Lighter is generally faster, and that will probably apply to top speed. Having a heavier car won't help matters at all...
So is there terminal velocity with any force on earth in any direction
As the air being displaced (air resistance ) and other forces acting against the car (friction gravity) is equal to the force applied by the engine?
And isn't the density of the size of object and is cross sectional surface area has more of an impact on the displacement of air ?
Sorry it's basic as I don't have much knowledge of physics (d-c at gcse at year 9)
Well, a lighter car has a better power to weight ratio witch makes it easier to ''move'' with the engine, so i guess lighter is better, but in a downhill more mass equals higher speed due to the 9.81 m/s acceleration in gravity...i think... or if anyone understands physics just tell :-)
My dad explained this well:
Imagine running 4km
Now try wearing a backpack that weighs 50~100 lbs and running 4km again
Which is easier?
I don't understand how weight is the only thing that affects surface friction, what about the friction coefficient for the tyre?
It weights 100kg and puts down 1,000N of force at the tyres.
It's irrelevant, beyond a very low level.
In terms of straight line speed, friction coefficient of the tyre is also only relevant to how much torque - not power - can be transmitted by the car to the road surface. Since, at top speed, the car is producing just about as little torque as it can manage (gearboxes multiply torque; high gear = low multiplier), what torque the tyre can cope with is irrelevant so long as it can maintain the paltry 2,000lbft or so the Veyron generates at the wheels in 7th gear.
Moreover, the friction of a tyre that isn't loaded is zero, regardless of the friction coefficient. The loading is what generates friction - this is, in part, why downforce and lift change this calculation.
However it's an irrelevance since the tyre on the 4150lb car doing its top speed run is the same as the tyre on the 3950lb car doing the same top speed run - it's a factor that can be normalised because it is effectively constant between the two tests.
In general, as I said, rolling resistance can be calculated by multiplying the vehicle mass by about 1.35%, though it can be changed by downforce or lift.
Just for reference, "100kg" is a mass, not a weight. "1000N" is both a weight and a force - since weight is force (mass multiplied by acceleration; in this case a mass of 100kg accelerated downwards by gravity to generate a weight).
That aside, you said that weight does not affect a car's top speed. If it has the gearing to exploit it then it does - just not by very much. Even a Veyron that weighed half as much as it does wouldn't be able to go that much faster than a normal one, without invoking relativistic speeds...
My point was was that when weight increases, tyre friction increases.
This means that the force put down by the tyre increases by the same amount as the rolling resistance force increases.
Yes and no. Yes, to a limit. But no, you're applying it to the whole car.
If you increased the mass of, say, a Mazda MX-5 by 10lb - big Christmas dinner - you don't increase the load on every tyre by 10lb. You increase the load on each tyre by 2.5lb. If you increase the mass of a Ford Focus RS by 10lb, you increase the load on each front (drive) tyre by 3.2lb and the load on each rear tyre by 1.8lb.
The amount of available grip on a drive tyre isn't coefficient of friction x vehicle weight, it's coefficient of friction x corner weight. More to the point here, it's coefficient of friction x instant corner weight as this weight can change wildly according to what you're doing at the time - a 50:50 (MX-5) or 63:37 (Focus) static weight distribution isn't very relevant when you're standing the car on its nose. Ultimately, adding 10lb to the mass of a car does not increase the mass on any one tyre by 10lb. Unless you're in the middle of a colossal crash and only one wheel is on the ground.
Which it won't do. The weight (or normal force) of the vehicle changes according to the overall vehicle loading, while the weight of an individual tyre changes according to the corner loading. The friction coefficient of the tyre on the road surface changes only according to the corner loading (and can be affected by other factors such as footprint, inflation and, amusingly, even the tread pattern).
But it's only relevant to the amount of torque and to a static vehicle. Notice how it's quite hard to get a car moving by pushing/pulling it, but quite easy to keep it moving once it's started?
it MUST be fast, it's a 4WD LOL
Well, a lighter car has a better power to weight ratio witch makes it easier to ''move'' with the engine, so i guess lighter is better, but in a downhill more mass equals higher speed due to the 9.81 m/s acceleration in gravity...i think... or if anyone understands physics just tell :-)
If you take a ten-pound box and a hundred-pound box of equal size and drop them at the same time from the same height, they will hit the ground at exactly the same time.
That isn't how gravity works. As an illustration, a light-weight object falls just as fast as a heavier one. The only reason that a sheet of paper or feather falls slower than a rock is air resistance, which has absolutely nothing to do with weight or gravity. If you take a ten-pound box and a hundred-pound box of equal size and drop them at the same time from the same height, they will hit the ground at exactly the same time.
That isn't how gravity works. As an illustration, a light-weight object falls just as fast as a heavier one. The only reason that a sheet of paper or feather falls slower than a rock is air resistance, which has absolutely nothing to do with weight or gravity. If you take a ten-pound box and a hundred-pound box of equal size and drop them at the same time from the same height, they will hit the ground at exactly the same time.
I feel like I'm in science class.
It goes as fast as the LMP2 cars not because it's half the weight of them but because (despite having half the power), it's got half the CdA!
Ultimate top speed is decided by power, aerodynamics and gearing
Weight will only effect acceleration
mjm_98How much impact does wind have ?
Sorry, but weight has no impact at all on ultimate top speed, if the road is flat and veery long