- 863
- oops_sorryy
Actually I found what you said to be very clear and it did clear up a few questions I had thought of, Thank You!
itstheDRE4M, it looks like you've put a fair bit of time into testing this, thanks for sharing your results.
Are you assuming loss of traction based on the tyre colour going red? If so, the red actually indicates that the tyre is overheating. This can be caused by cornering/braking/acceleration, so it's not necessarily wheelspin aka loss of traction. A clutch-pack LSD isn't ever capable of spinning the outside wheel, so the red in this case is probably due to cornering grip.
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Cool, if that's what you're seeing I can't argue with that!I'm not assuming it due to the tire turning red on the diagram.
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I am assuming it because of the tire marks left on the exit of corners.
Cool, if that's what you're seeing I can't argue with that!
I just wanna say in real life it's not possible to spin the outside tyre before the inside.
I'm following up on my testing right now. I changed cars and got basically the same results. I'll be posting a thread illustrating my findings.
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To answer the OPs question, here's how I used LSD initial
- increasing it resists the car yawing (makes the car harder to turn)
- high initial instead of high accel+decel (eg 30/10/10 vs 10/30/30) avoids quirky handling due to changes as throttle is applied/released
- often I use initial to reduce lift-off oversteer in MR and RR
- the real life equivalent is LSD pre-load, which is the torque difference between the wheels that is required to unlock the diff. Until cornering causes a greater torque difference than the pre-load value (in Nm or ft-lb), the diff is locked so the car is harder to turn. I highly doubt that the "LSD initial" value is in Nm or lb-ft, it is just an arbitary scale between no pre-load (0) and always locked (60)
[CENTER]more torque difference
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locked - open - locked
initial (+) accel/decel (+)
inside wheel outside wheel
[/CENTER]
All initial torque is is how fast and hard it will kick the LSD in and accel setting relates to it, but having it set low locks and high unlocks the diff.
I think its the other way around. The inside spins first if the diff is unlocked because it is unloaded and has no weight on it, so a free turning diff sends all the power there(think of a off roader with no lock diff, if 1 wheel is in the air, that wheel spins and the car goes nowhere)I see why you describe it like that. As I understand it what happens though is you give too much throttle out of the corner making the outer wheel spin first (because it has to use it's grip for cornering). This will lock the LSD (according to your accel-setting) and therefor giving more torque to the inside wheel. But the inside wheel loses traction too immediately after, which makes both wheels rotate equally, which causes the LSD to lock more according to your initial value.
Am I right?
I think its the other way around. The inside spins first if the diff is unlocked because it is unloaded and has no weight on it, so a free turning diff sends all the power there(think of a off roader with no lock diff, if 1 wheel is in the air, that wheel spins and the car goes nowhere)
Then depending on the initial torque setting, the diff will lock, and send equal power to both wheels.
You're right, but the result is the same and that was my point.
Edit: Actually both can happen. At least in GT5 the outside wheel can spin first.
I think its the other way around. The inside spins first if the diff is unlocked because it is unloaded and has no weight on it, so a free turning diff sends all the power there(think of a off roader with no lock diff, if 1 wheel is in the air, that wheel spins and the car goes nowhere)
Then depending on the initial torque setting, the diff will lock, and send equal power to both wheels.
I think the accel and brake settings adjust how freely the diff turns when its unlocked, the higher the setting, the more the diff resists turning in an unlocked state, making the car understeer more, or under acceleration in a high power rear drive car, can create oversteer(instead of the inside wheel spining and the car losing drive traction, breaks rear traction completely by spining both wheels)
The only reason the outside spins first is because it is at full lock and has all of the weight on it making it so the inside wheel is barely touching and cant really burn.
Wouldn't this mean that the lower initial torque would create understeer? It seems to do the opposite in gameYou are right but have it opposite, the Initial Torque is how freely it turns when its unlocked and how easy it is to lock, a lower # means it will turn less freely and be more locked
Not if your accelerating. The torque with an open diff will always go to the inside wheel(unloaded) because its the path of least resistance. If the diff is open, in theory the outside wheel cant spin unless the diff has a setting that makes it tight to turn when open(not locked)Are you sure you have locked and open right? From my understanding locked refers to both wheels getting the same torque (forced). Under turning the outside wheel can indeed never spin before the inside wheel if the LSD is locked. Simply because the outside wheel has to be faster to corner.
The outside wheel spinning first can happen though if the LSD is open at that point. The reason is probably that the inner wheel will not lift off the ground in GT5.
Not if your accelerating. The torque with an open diff will always go to the inside wheel(unloaded) because its the path of least resistance. If the diff is open, in theory the outside wheel cant spin unless the diff has a setting that makes it tight to turn when open(not locked)
Not if your accelerating. The torque with an open diff will always go to the inside wheel(unloaded) because its the path of least resistance.
PoppinsYes you are right, if the diff is open it will ALWAYS be the inside tire as it is spinning the slowest and has the least weight and traction on it.
The reason the outside spins is because it locks the inside one up right away causing it to lose lateral traction and go sideways putting weight and pressure on the outside wheel. You need to be on a straight stretch to test the locking like I said already. But it should be easy enough to figure out that having Initial Torque set to 60 causes inside tire spin, which means the diff is open. Pretty simple logic for anyone who knows how it actually works.
Hahaha thats sig material.PS its not you im arguing with just other people who wont think about it for 5 seconds and see how dumb they are
well i know for a fact that i get one tire fire when initial torque is set too high so all of my cars have it at 10 ish.
Link: https://www.gtplanet.net/forum/showthread.php?t=148947&page=2The best LSD you're probably going to get on average without fine tuning is more along the lines of 30/50/15 maybe 30/45/20~ somewhere around there
Wao! Imagine my surprise, I leave this thread for a couple hours and we get a lively discussion! Thank you Poppins, Z1-AV69, and Will27 for your thoughts. Seems as if things are heating up around here.
Nah I live in Canada eh so its not even 8 pm here yet.
And it really, really makes me happy to see your false information off this forum.
Thanks for getting my thread closed POPPINS!
Go to bed.