I didn't quite phrase it the way I meant to.
What I was getting at is that the efficiency of a Skyactiv-D in a car varies according to all sorts of different factors in context of moving a vehicle from point A to point B - gearing, rolling resistance, aerodynamic resistance, gravity.
(A)An engine spinning at 4000rpm will use a set amount of fuel (all other factors being equal), but how efficiently that fuel is used depends on what you're doing with the output. (B)If you're driving up a hill in second gear at 4000rpm the same amount of fuel will get you a shorter distance than if you're in sixth gear on a flat road at the same revs - (C)and the same engine spinning a generator at the same speed will probably be an even more efficient use of energy for a given distance.
(A): Not necessarily true and i'm not sure what you mean by other factors being equal. An engine with zero load at 4,000rpm will barely use any fuel. An engine at 100% load at 4,000rpm will use a lot of fuel, relatively speaking
(B): That depends on quite a lot of factors. How steep the hill is, what the gearing is, what the total drag of the vehicle is. The vehicle on the hill is likely to consume more fuel, but I wouldn't say its impossible for it to consume less. If the total load of the aerodynamic drag (remember, it squares with velocity) is greater than the gravity load of the vehicle on the hill, its reasonable to imagine that the car on the highway has higher fuel consumption/shorter range.
(C): Again, engine speed has much less correlation to fuel consumption than load does. It's entirely possible that option C could be the least efficient use of the engine's output, in some situations, because you are converting kinetic energy to electric energy, and then converting electric energy to kinetic energy again. You will still have some parasitic loss through mechanical inefficiency just as the engine-driven car does, but you're also now introducing loss due to electric motor inefficiency.
Example:
Car 1: 100kw ICE (@ peak efficiency)
Car 2: 100kw ICE (@ peak efficiency) + 100kw EM
In car 1, assuming a modern front drive vehicle, you'll probably get to use about 90-95kw of that engine output for moving the vehicle, at peak efficiency.
In car 2, assuming some drivetrain loss + electric motor losses, you'll probably be getting less than 90kw of that engine output for moving the vehicle, at peak efficiency.
The difference is that car 1 will be operating at peak efficiency rarely, and car 2 could be operating at peak efficiency much more often, depending on a large variety of factors.
Anyone else hyped for the reveals later this month??