@ MrktMkr1986:
Yes, that's absoulutely right đź‘Ť Good job.
Only thing, substitute this: sqrt(b^2-4ac)/4a^2
with this: sqrt[(b^2-4ac)/4a^2]
(as both numerator and denominator need to be under the square root)
and this: x = -b +/- sqrt (b^2-4ac)/2a
with this: x = [-b +/- sqrt (b^2-4ac)]/2a
(as the whole expression needs to be divided by 2a, not just the term sqrt (b^2-4ac))
Other than that, the derivation process was perfect!
EDIT: If you/somebody in general needs help in math or the such, we may want to start a thread just for that, lol! As this has little to do with the nickname discussion
![Big Grin :D :D](/wp-content/themes/gtp16/images/smilies/biggrin.svg?v=3)
Not being mean or anything... And, I am serious about the thread... I bet it would be useful for a lot of
students here in GTPlanet... and of course, I wouldn't be the only
teacher ![Cool :cool: :cool:](/wp-content/themes/gtp16/images/smilies/cool.svg?v=3)
Other people can help too.
EDIT II: I would stay and discuss math some more, but I have an Aircraft Structures II assignment to work on that's due tomorrow... so I'll have to retire for an hour or two...
The Wizard.