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- kilesa4568
(Torque x Rotational Speed x C) = (10 x Torque x 1/10 Rotational Speed x C) = Power
If you can't make sense of that then there is nothing anyone can do to help you understand this.
I'm glad I just do the driving.
(Torque x Rotational Speed x C) = (10 x Torque x 1/10 Rotational Speed x C) = Power
If you can't make sense of that then there is nothing anyone can do to help you understand this.
What about coasting before braking?
I have no idea what you are trying to illustrate, but, if you cannot see that you have changed 100Nm to 1000Nm (which is indeed changing the power) to somehow support your math, there is nothing anyone can do to help you understand this.
Electric motors produce a nearly flat TQ curve from 1rpm on, and is why they do not need a gearbox. It's not that they produce low end or high end, rather virtually unchanged power continuous across it's operating range/rpm.
What? the example I quoted, was where you were adding multipliers to the TQ, then changing the gear ratio to solve some math issue.
All I was illustrating is that you cannot add a multiplier to the source power... it is simply TQxgear ratio, not "#"xTQ x gear ratio.
here, I will re-quote...
TQ at the flywheel is unchanged, the frictional losses will be measured at the wheels.
No gearbox/clutch on the planet will change the source power... it will effect the driven wheels.
The only part you need to understand is that the 10 and the 1/10 cancel each other.I'm glad I just do the driving
The torque in an electric motor is immediate and flat. the power increases as the rpm increase.You’re mixing up torque with power again. The power curve of an electric motor is nearly flat, not the torque curve.
Nope, it’s connected by the clutch, so friction of the gearbox affects the torque at the flywheel as well. It’s one and the same system.
Okay guys please. I understand that you're trying to figure out the exact math to prove your... whatever it is. But the main concern for me is... where's the proof? Here is a link in a race with the amg gt3 (the key point here it's that it's real.) So look at the rev limiter and tell me if he is shifting half way to save fuel.
They do indeed short shift. When coming out of corners. I've watched plenty of onboards and live streams and have not been able to catch anyone short shifting for the entirety of the race.Hmm, try looking at LMP1s maybe? I'm not 100% sure, but they do have limitations on how much fuel they need to use over the course of a certain amount of laps. So there you'll see more fuel-saving. There's lifting, and maybe shortshifting
Ahhh. Interesting, that's something new to learnThey do indeed short shift. When coming out of corners. I've watched plenty of onboards and live streams and have not been able to catch anyone short shifting for the entirety of the race.
I really want to understand this...(Torque x Rotational Speed x C) = (10 x Torque x 1/10 Rotational Speed x C) = Power
he is showing that the variables are inversely proportional to eachother.I really want to understand this...
Why are you multiplying TQ by 10?
Why are you then dividing rpm by 10?
If you have a link of an lmp1 onboard in which they DO. Then please link me to it.Ahhh. Interesting, that's something new to learn
However in gts you have to do it manually.
Same here, I like Foghorn Leghorn when people talk this long head stuff.
Too many variables come into play to to use one rule of thumb as far as what RPM an engine will give the best performance in relation to dyno horsepower and torque numbers.
Displacement, bore, stroke all greatly affect where and how an engine makes power. Camshift lift and valve timing as far as whether the camshaft is advanced or retarded when installed will affect the power curve as well. Then we get into ignition timing, like I said so many different things control or can alter how an engine makes or delivers its power.
This is the reason that you can have two engines from the same manufacturer with the same cubic inch displacement and one will excel at under 5000 RPMS pulling the trailer to the track and the others strong point will be at 8500 RPM motivating a much lighter race car down the track.
Switch those two motors between the two vehicles and neither will perform adequately of the different task they would then be expected to perform.
Everything in the drivetrain and the vehicle it is installed in must be matched to all perform the same goal of the maximum performance of the task they were built to do.
Back when I use to drag race I preferred the big block torque and pull that I got out of the higher gears on the top end that I could not get out of the small blocks. The small blocks relied more on quick high revving rpms to make their power and if you tried to twist a big block that high you were just going to turn your engine into a grenade!
Again two different methods of trying to obtain the same goal which in this case was covering a 1/4 mile from a standing start in as short a time as possible.
A 10:1 combined gear ratio will give you 10 times the wheel torque while reducing the speed of the driven wheels by a factor of 10.I really want to understand this...
Why are you multiplying TQ by 10?
Why are you then dividing rpm by 10?
Fun fact. I was in the pub that day.
First off, thank you for the straight response.A 10:1 combined gear ratio will give you 10 times the wheel torque while reducing the speed of the driven wheels by a factor of 10.
I'll focus just these 2 statements, ignoring there were a multitude of misconstrued facts along the way, which have been conveniently edited...1. That means that the power at the wheel is the same as the power at the flywheel.
2. 2 torque x 4 speed is the same power (8) as 4 torque x 2 speed.
I'm rather certain this is incorrect... I mean simple math will defend this (x10 then /10), but...You can do more work, but slower. The rate at which work is done remains constant.
Fun fact. I was in the pub that day.
The torque in an electric motor is immediate and flat. the power increases as the rpm increase.
The actual torque output that an engine makes is measured at the crankshaft/ flywheel of the engine with none of the drivetrain attached and is advertised as such.
1. You yourself have noted that power at the wheel is manipulated by gearing... first quote of this post... and is what i have said from the beginning.
2. The second example clearly applies a multiplier to TQ
then adjusts gearing to justify simple arithmetic...
No, that was torque. Torque is not power.1. You yourself have noted that power at the wheel is manipulated by gearing... first quote of this post... and is what i have said from the beginning.
It's the other way around, changing the gear ratio will affect the torque and speed. The whole point was to show that the power is not multiplied by gearing.2. The second example clearly applies a multiplier to TQ, then adjusts gearing to justify simple arithmetic... but has no relevance in a engine/transmission/diff/wheel power delivery system.
Oh...eh...I wasn't in that pub.HeheheDiscussing the rudiments of torque?
Sure, but when driving the engine is connected to the rest of the drivetrain so the frictional losses of the drivetrain applies to engine torque as well, other you’d have one power at the flywheel and another power at the driven wheel and and that is physically impossible for a connected system.
wait a minute... all this time your term "speed" is driven wheel speed... not engine rpm?4Nm at 2rad/s = 8W
Now, apply a gear ratio of 0.5:
4Nm*0.5 at 2rad/s/0.5 =
2Nm * 4rad/s = 8W
The gear ratio of 0.5 halved the torque and doubled the speed. Power remains 8W and did NOT change. That’s N-O-T for not. Do you read me, over?
4*2 = 8
2*4 = 8
We need to drop it.Which would be correct...
Right here we have doubled the rpm, but ignored the fact that... that in and of itself has changed the TQ value in a non-linear amount.A 2:1 gear ratio will rotate the engine twice for every turn of the drive wheel. That means you get twice as many combustion events per rotation of the driven wheel. Twice the torque...
I see the misunderstanding now. When I say double the torque and half the speed I mean at the same rpm in a different gear.Right here we have doubled the rpm, but ignored the fact that... that in and of itself has changed the TQ value in a non-linear amount.
I'm out.